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135467923500073 is a prime number
BaseRepresentation
bin11110110011010100010101…
…011101010110110000101001
3122202122121101111202002122201
4132303110111131112300221
5120224001301404000243
61200041034355020201
740351143300454633
oct3663242535266051
9582577344662581
10135467923500073
113a1896951a100a
121323a71159a661
135a78755151838
14256497aa2da53
15109dc7185004d
hex7b3515756c29

135467923500073 has 2 divisors, whose sum is σ = 135467923500074. Its totient is φ = 135467923500072.

The previous prime is 135467923499981. The next prime is 135467923500109. The reversal of 135467923500073 is 370005329764531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 135271717025769 + 196206474304 = 11630637^2 + 442952^2 .

It is a cyclic number.

It is not a de Polignac number, because 135467923500073 - 29 = 135467923499561 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135467923499987 and 135467923500023.

It is not a weakly prime, because it can be changed into another prime (135467923506073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67733961750036 + 67733961750037.

It is an arithmetic number, because the mean of its divisors is an integer number (67733961750037).

Almost surely, 2135467923500073 is an apocalyptic number.

It is an amenable number.

135467923500073 is a deficient number, since it is larger than the sum of its proper divisors (1).

135467923500073 is an equidigital number, since it uses as much as digits as its factorization.

135467923500073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14288400, while the sum is 55.

The spelling of 135467923500073 in words is "one hundred thirty-five trillion, four hundred sixty-seven billion, nine hundred twenty-three million, five hundred thousand, seventy-three".