Base | Representation |
---|---|
bin | 1100010100101011000010… |
… | …0100000110101000100001 |
3 | 1202222022002020212020211201 |
4 | 3011022300210012220201 |
5 | 3233442421002342303 |
6 | 44452242452241201 |
7 | 2565622005100306 |
oct | 305126044065041 |
9 | 52868066766751 |
10 | 13549289105953 |
11 | 435424851aaa7 |
12 | 1629b39610201 |
13 | 7739004c1033 |
14 | 34bb093a70ad |
15 | 1876ac53981d |
hex | c52b0906a21 |
13549289105953 has 2 divisors, whose sum is σ = 13549289105954. Its totient is φ = 13549289105952.
The previous prime is 13549289105917. The next prime is 13549289105971. The reversal of 13549289105953 is 35950198294531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13428061882624 + 121227223329 = 3664432^2 + 348177^2 .
It is an emirp because it is prime and its reverse (35950198294531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13549289105953 - 213 = 13549289097761 is a prime.
It is not a weakly prime, because it can be changed into another prime (13549289105983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6774644552976 + 6774644552977.
It is an arithmetic number, because the mean of its divisors is an integer number (6774644552977).
Almost surely, 213549289105953 is an apocalyptic number.
It is an amenable number.
13549289105953 is a deficient number, since it is larger than the sum of its proper divisors (1).
13549289105953 is an equidigital number, since it uses as much as digits as its factorization.
13549289105953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488000, while the sum is 64.
The spelling of 13549289105953 in words is "thirteen trillion, five hundred forty-nine billion, two hundred eighty-nine million, one hundred five thousand, nine hundred fifty-three".
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