Base | Representation |
---|---|
bin | 1100010100101110011010… |
… | …1100101000011110000111 |
3 | 1202222101102112210212110021 |
4 | 3011023212230220132013 |
5 | 3234001301002430432 |
6 | 44452512534240011 |
7 | 2565653343522433 |
oct | 305134654503607 |
9 | 52871375725407 |
10 | 13550197311367 |
11 | 4354674147192 |
12 | 162a1517b6007 |
13 | 773a166cb4a2 |
14 | 34bb93c5b9c3 |
15 | 187712137697 |
hex | c52e6b28787 |
13550197311367 has 2 divisors, whose sum is σ = 13550197311368. Its totient is φ = 13550197311366.
The previous prime is 13550197311353. The next prime is 13550197311383. The reversal of 13550197311367 is 76311379105531.
13550197311367 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13550197311367 - 227 = 13550063093639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13550197312367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775098655683 + 6775098655684.
It is an arithmetic number, because the mean of its divisors is an integer number (6775098655684).
Almost surely, 213550197311367 is an apocalyptic number.
13550197311367 is a deficient number, since it is larger than the sum of its proper divisors (1).
13550197311367 is an equidigital number, since it uses as much as digits as its factorization.
13550197311367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1786050, while the sum is 52.
The spelling of 13550197311367 in words is "thirteen trillion, five hundred fifty billion, one hundred ninety-seven million, three hundred eleven thousand, three hundred sixty-seven".
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