Base | Representation |
---|---|
bin | 10011101101111101100… |
… | …011010011111111110101 |
3 | 11210112112202021022000221 |
4 | 103231331203103333311 |
5 | 134200040400412224 |
6 | 2514253232534341 |
7 | 166616454241531 |
oct | 23557543237765 |
9 | 4715482238027 |
10 | 1355021107189 |
11 | 4827300a9402 |
12 | 19a7419b13b1 |
13 | 9aa161a60b9 |
14 | 49824ab2bc1 |
15 | 253a94e06e4 |
hex | 13b7d8d3ff5 |
1355021107189 has 2 divisors, whose sum is σ = 1355021107190. Its totient is φ = 1355021107188.
The previous prime is 1355021107183. The next prime is 1355021107211. The reversal of 1355021107189 is 9817011205531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 974449328164 + 380571779025 = 987142^2 + 616905^2 .
It is a cyclic number.
It is not a de Polignac number, because 1355021107189 - 217 = 1355020976117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1355021107183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677510553594 + 677510553595.
It is an arithmetic number, because the mean of its divisors is an integer number (677510553595).
Almost surely, 21355021107189 is an apocalyptic number.
It is an amenable number.
1355021107189 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355021107189 is an equidigital number, since it uses as much as digits as its factorization.
1355021107189 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 43.
The spelling of 1355021107189 in words is "one trillion, three hundred fifty-five billion, twenty-one million, one hundred seven thousand, one hundred eighty-nine".
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