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135503354626511 is a prime number
BaseRepresentation
bin11110110011110101010101…
…010100011000000111001111
3122202202222211202122210212212
4132303311111110120013033
5120230041332241022021
61200105214243021035
740353536306202434
oct3663652524300717
9582688752583785
10135503354626511
113a1a2717137793
121324555b36a77b
135a7bbb0794701
14256657c4c3b8b
15109eb4719185b
hex7b3d555181cf

135503354626511 has 2 divisors, whose sum is σ = 135503354626512. Its totient is φ = 135503354626510.

The previous prime is 135503354626501. The next prime is 135503354626537. The reversal of 135503354626511 is 115626453305531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 135503354626511 - 234 = 135486174757327 is a prime.

It is a super-2 number, since 2×1355033546265112 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 135503354626511.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135503354626501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67751677313255 + 67751677313256.

It is an arithmetic number, because the mean of its divisors is an integer number (67751677313256).

Almost surely, 2135503354626511 is an apocalyptic number.

135503354626511 is a deficient number, since it is larger than the sum of its proper divisors (1).

135503354626511 is an equidigital number, since it uses as much as digits as its factorization.

135503354626511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860000, while the sum is 50.

The spelling of 135503354626511 in words is "one hundred thirty-five trillion, five hundred three billion, three hundred fifty-four million, six hundred twenty-six thousand, five hundred eleven".