1355040302437 has 2 divisors, whose sum is σ = 1355040302438. Its totient is φ = 1355040302436.

The previous prime is 1355040302281. The next prime is 1355040302443. The reversal of 1355040302437 is 7342030405531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1181625524676 + 173414777761 = 1087026^2 + 416431^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355040302437 - 2¹¹ = 1355040300389 is a prime.

It is a super-2 number, since 2×1355040302437² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1355040302396 and 1355040302405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1355040302477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677520151218 + 677520151219.

It is an arithmetic number, because the mean of its divisors is an integer number (677520151219).

Almost surely, 2^{1355040302437} is an apocalyptic number.

It is an amenable number.

1355040302437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355040302437 is an equidigital number, since it uses as much as digits as its factorization.

1355040302437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 37.

Adding to 1355040302437 its reverse (7342030405531), we get a palindrome (8697070707968).

The spelling of 1355040302437 in words is "one trillion, three hundred fifty-five billion, forty million, three hundred two thousand, four hundred thirty-seven".