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13550515104661 is a prime number
BaseRepresentation
bin1100010100101111100110…
…1000111010101110010101
31202222102020200210102220021
43011023321220322232111
53234002423331322121
644453004245505141
72565664252650463
oct305137150725625
952872220712807
1013550515104661
114354817573a77
12162a2201121b1
13773a674b9162
1434bbc4143833
1518772eead641
hexc52f9a3ab95

13550515104661 has 2 divisors, whose sum is σ = 13550515104662. Its totient is φ = 13550515104660.

The previous prime is 13550515104647. The next prime is 13550515104703. The reversal of 13550515104661 is 16640151505531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8840721022225 + 4709794082436 = 2973335^2 + 2170206^2 .

It is an emirp because it is prime and its reverse (16640151505531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13550515104661 - 25 = 13550515104629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13550515104461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775257552330 + 6775257552331.

It is an arithmetic number, because the mean of its divisors is an integer number (6775257552331).

Almost surely, 213550515104661 is an apocalyptic number.

It is an amenable number.

13550515104661 is a deficient number, since it is larger than the sum of its proper divisors (1).

13550515104661 is an equidigital number, since it uses as much as digits as its factorization.

13550515104661 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270000, while the sum is 43.

The spelling of 13550515104661 in words is "thirteen trillion, five hundred fifty billion, five hundred fifteen million, one hundred four thousand, six hundred sixty-one".