Base | Representation |
---|---|
bin | 11110110011110111010000… |
… | …101100000011110011011011 |
3 | 122202210012012000100211201021 |
4 | 132303313100230003303123 |
5 | 120230110102123313342 |
6 | 1200110155502103311 |
7 | 40353641511231664 |
oct | 3663672054036333 |
9 | 582705160324637 |
10 | 135505424432347 |
11 | 3a1a3589522522 |
12 | 13245a3857ab37 |
13 | 5a7c1505400a8 |
14 | 25666d735036b |
15 | 109ec18c42567 |
hex | 7b3dd0b03cdb |
135505424432347 has 2 divisors, whose sum is σ = 135505424432348. Its totient is φ = 135505424432346.
The previous prime is 135505424432263. The next prime is 135505424432359. The reversal of 135505424432347 is 743234424505531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135505424432347 - 219 = 135505423908059 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135505424432294 and 135505424432303.
It is not a weakly prime, because it can be changed into another prime (135505424432377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67752712216173 + 67752712216174.
It is an arithmetic number, because the mean of its divisors is an integer number (67752712216174).
Almost surely, 2135505424432347 is an apocalyptic number.
135505424432347 is a deficient number, since it is larger than the sum of its proper divisors (1).
135505424432347 is an equidigital number, since it uses as much as digits as its factorization.
135505424432347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192000, while the sum is 52.
Adding to 135505424432347 its reverse (743234424505531), we get a palindrome (878739848937878).
The spelling of 135505424432347 in words is "one hundred thirty-five trillion, five hundred five billion, four hundred twenty-four million, four hundred thirty-two thousand, three hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •