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135505424432377 is a prime number
BaseRepresentation
bin11110110011110111010000…
…101100000011110011111001
3122202210012012000100211202101
4132303313100230003303321
5120230110102123314002
61200110155502103401
740353641511232036
oct3663672054036371
9582705160324671
10135505424432377
113a1a358952254a
1213245a3857ab61
135a7c1505400cc
1425666d735038d
15109ec18c42587
hex7b3dd0b03cf9

135505424432377 has 2 divisors, whose sum is σ = 135505424432378. Its totient is φ = 135505424432376.

The previous prime is 135505424432359. The next prime is 135505424432407. The reversal of 135505424432377 is 773234424505531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104789842629481 + 30715581802896 = 10236691^2 + 5542164^2 .

It is a cyclic number.

It is not a de Polignac number, because 135505424432377 - 219 = 135505423908089 is a prime.

It is a super-2 number, since 2×1355054244323772 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135505424432347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67752712216188 + 67752712216189.

It is an arithmetic number, because the mean of its divisors is an integer number (67752712216189).

Almost surely, 2135505424432377 is an apocalyptic number.

It is an amenable number.

135505424432377 is a deficient number, since it is larger than the sum of its proper divisors (1).

135505424432377 is an equidigital number, since it uses as much as digits as its factorization.

135505424432377 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42336000, while the sum is 55.

The spelling of 135505424432377 in words is "one hundred thirty-five trillion, five hundred five billion, four hundred twenty-four million, four hundred thirty-two thousand, three hundred seventy-seven".