Base | Representation |
---|---|
bin | 11110110011110111010101… |
… | …010100011000000111001110 |
3 | 122202210012101102112021122020 |
4 | 132303313111110120013032 |
5 | 120230110232020011113 |
6 | 1200110211315031010 |
7 | 40353643443413625 |
oct | 3663672524300716 |
9 | 582705342467566 |
10 | 135505502110158 |
11 | 3a1a3619357a64 |
12 | 13245a5a59b466 |
13 | 5a7c1636694ab |
14 | 25667037b06bc |
15 | 109ec20988023 |
hex | 7b3dd55181ce |
135505502110158 has 32 divisors (see below), whose sum is σ = 271122792775296. Its totient is φ = 45149870626848.
The previous prime is 135505502110007. The next prime is 135505502110159. The reversal of 135505502110158 is 851011205505531.
It is a super-2 number, since 2×1355055021101582 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135505502110159) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 440883285 + ... + 441190527.
It is an arithmetic number, because the mean of its divisors is an integer number (8472587274228).
Almost surely, 2135505502110158 is an apocalyptic number.
135505502110158 is an abundant number, since it is smaller than the sum of its proper divisors (135617290665138).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135505502110158 is a wasteful number, since it uses less digits than its factorization.
135505502110158 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 337328.
The product of its (nonzero) digits is 150000, while the sum is 42.
Adding to 135505502110158 its reverse (851011205505531), we get a palindrome (986516707615689).
The spelling of 135505502110158 in words is "one hundred thirty-five trillion, five hundred five billion, five hundred two million, one hundred ten thousand, one hundred fifty-eight".
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