Search a number
-
+
135512115131 is a prime number
BaseRepresentation
bin111111000110100100…
…1101100011110111011
3110221210001221201002002
41332031021230132323
54210012100141011
6142130422531215
712535054654601
oct1761511543673
9427701851062
10135512115131
115251a068888
122231a896b0b
13ca17b6aa13
1467b7597871
1537d1c27c3b
hex1f8d26c7bb

135512115131 has 2 divisors, whose sum is σ = 135512115132. Its totient is φ = 135512115130.

The previous prime is 135512115127. The next prime is 135512115157. The reversal of 135512115131 is 131511215531.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 135512115131 - 22 = 135512115127 is a prime.

It is a super-2 number, since 2×1355121151312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 135512115094 and 135512115103.

It is not a weakly prime, because it can be changed into another prime (135512115731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67756057565 + 67756057566.

It is an arithmetic number, because the mean of its divisors is an integer number (67756057566).

Almost surely, 2135512115131 is an apocalyptic number.

135512115131 is a deficient number, since it is larger than the sum of its proper divisors (1).

135512115131 is an equidigital number, since it uses as much as digits as its factorization.

135512115131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2250, while the sum is 29.

The spelling of 135512115131 in words is "one hundred thirty-five billion, five hundred twelve million, one hundred fifteen thousand, one hundred thirty-one".