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135512354550049 is a prime number
BaseRepresentation
bin11110110011111101101101…
…110000010111000100100001
3122202210212001222121022000021
4132303331231300113010201
5120230213300231100144
61200113303302353441
740354305321244531
oct3663755560270441
9582725058538007
10135512354550049
113a1a6515386524
121324725142b881
135a7c9b6218c59
142566b938b94c1
15109eec2355884
hex7b3f6dc17121

135512354550049 has 2 divisors, whose sum is σ = 135512354550050. Its totient is φ = 135512354550048.

The previous prime is 135512354550011. The next prime is 135512354550103. The reversal of 135512354550049 is 940055453215531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82511916130449 + 53000438419600 = 9083607^2 + 7280140^2 .

It is an emirp because it is prime and its reverse (940055453215531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135512354550049 - 217 = 135512354418977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135512354549978 and 135512354550005.

It is not a weakly prime, because it can be changed into another prime (135512354550449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67756177275024 + 67756177275025.

It is an arithmetic number, because the mean of its divisors is an integer number (67756177275025).

Almost surely, 2135512354550049 is an apocalyptic number.

It is an amenable number.

135512354550049 is a deficient number, since it is larger than the sum of its proper divisors (1).

135512354550049 is an equidigital number, since it uses as much as digits as its factorization.

135512354550049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100000, while the sum is 52.

The spelling of 135512354550049 in words is "one hundred thirty-five trillion, five hundred twelve billion, three hundred fifty-four million, five hundred fifty thousand, forty-nine".