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13551265364353 is a prime number
BaseRepresentation
bin1100010100110010011001…
…0110111011100110000001
31202222111011222112120201021
43011030212112323212001
53234010442413124403
644453210530305441
72566021663030513
oct305144626734601
952874158476637
1013551265364353
114355072021202
12162a3ab428281
13773b56a74bc2
1434bc55a41bb3
15187775cac8bd
hexc53265bb981

13551265364353 has 2 divisors, whose sum is σ = 13551265364354. Its totient is φ = 13551265364352.

The previous prime is 13551265364333. The next prime is 13551265364381. The reversal of 13551265364353 is 35346356215531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7912198256769 + 5639067107584 = 2812863^2 + 2374672^2 .

It is a cyclic number.

It is not a de Polignac number, because 13551265364353 - 229 = 13550728493441 is a prime.

It is a super-2 number, since 2×135512653643532 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13551265364353.

It is not a weakly prime, because it can be changed into another prime (13551265364323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775632682176 + 6775632682177.

It is an arithmetic number, because the mean of its divisors is an integer number (6775632682177).

Almost surely, 213551265364353 is an apocalyptic number.

It is an amenable number.

13551265364353 is a deficient number, since it is larger than the sum of its proper divisors (1).

13551265364353 is an equidigital number, since it uses as much as digits as its factorization.

13551265364353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14580000, while the sum is 52.

The spelling of 13551265364353 in words is "thirteen trillion, five hundred fifty-one billion, two hundred sixty-five million, three hundred sixty-four thousand, three hundred fifty-three".