Base | Representation |
---|---|
bin | 10011101110000101001… |
… | …111001101110011111011 |
3 | 11210112212201220121111201 |
4 | 103232011033031303323 |
5 | 134200321403303244 |
6 | 2514314120435031 |
7 | 166622611265605 |
oct | 23560517156373 |
9 | 4715781817451 |
10 | 1355150056699 |
11 | 48279697304a |
12 | 19a779018a77 |
13 | 9aa36b1469a |
14 | 49837c7c175 |
15 | 253b59b2ad4 |
hex | 13b853cdcfb |
1355150056699 has 2 divisors, whose sum is σ = 1355150056700. Its totient is φ = 1355150056698.
The previous prime is 1355150056697. The next prime is 1355150056717. The reversal of 1355150056699 is 9966500515531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1355150056699 - 21 = 1355150056697 is a prime.
Together with 1355150056697, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1355150056693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677575028349 + 677575028350.
It is an arithmetic number, because the mean of its divisors is an integer number (677575028350).
Almost surely, 21355150056699 is an apocalyptic number.
1355150056699 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355150056699 is an equidigital number, since it uses as much as digits as its factorization.
1355150056699 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5467500, while the sum is 55.
The spelling of 1355150056699 in words is "one trillion, three hundred fifty-five billion, one hundred fifty million, fifty-six thousand, six hundred ninety-nine".
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