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135521440181 is a prime number
BaseRepresentation
bin111111000110110110…
…1010001000110110101
3110221210201111110122022
41332031231101012311
54210021442041211
6142131354442525
712535230143411
oct1761555210665
9427721443568
10135521440181
1152524357936
1222321a33445
13ca19a842ba
1467b8903d41
1537d296abdb
hex1f8db511b5

135521440181 has 2 divisors, whose sum is σ = 135521440182. Its totient is φ = 135521440180.

The previous prime is 135521440151. The next prime is 135521440231. The reversal of 135521440181 is 181044125531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82963585156 + 52557855025 = 288034^2 + 229255^2 .

It is a cyclic number.

It is not a de Polignac number, because 135521440181 - 226 = 135454331317 is a prime.

It is a super-2 number, since 2×1355214401812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135521440151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67760720090 + 67760720091.

It is an arithmetic number, because the mean of its divisors is an integer number (67760720091).

Almost surely, 2135521440181 is an apocalyptic number.

It is an amenable number.

135521440181 is a deficient number, since it is larger than the sum of its proper divisors (1).

135521440181 is an equidigital number, since it uses as much as digits as its factorization.

135521440181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 35.

The spelling of 135521440181 in words is "one hundred thirty-five billion, five hundred twenty-one million, four hundred forty thousand, one hundred eighty-one".