Base | Representation |
---|---|
bin | 10011101110001010000… |
… | …101010000111010011101 |
3 | 11210120002101211221001210 |
4 | 103232022011100322131 |
5 | 134201003210142140 |
6 | 2514330142455033 |
7 | 166624616162031 |
oct | 23561205207235 |
9 | 4716071757053 |
10 | 1355231334045 |
11 | 482828836a06 |
12 | 19a7a0294479 |
13 | 9aa4a9012a4 |
14 | 498449981c1 |
15 | 253bcbb9d80 |
hex | 13b8a150e9d |
1355231334045 has 32 divisors (see below), whose sum is σ = 2216680058880. Its totient is φ = 706716937280.
The previous prime is 1355231334013. The next prime is 1355231334053. The reversal of 1355231334045 is 5404331325531.
It is not a de Polignac number, because 1355231334045 - 25 = 1355231334013 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1355231333994 and 1355231334012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 224841 + ... + 1661630.
It is an arithmetic number, because the mean of its divisors is an integer number (69271251840).
Almost surely, 21355231334045 is an apocalyptic number.
1355231334045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1355231334045 is a deficient number, since it is larger than the sum of its proper divisors (861448724835).
1355231334045 is a wasteful number, since it uses less digits than its factorization.
1355231334045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1887545.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 1355231334045 its reverse (5404331325531), we get a palindrome (6759562659576).
The spelling of 1355231334045 in words is "one trillion, three hundred fifty-five billion, two hundred thirty-one million, three hundred thirty-four thousand, forty-five".
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