Base | Representation |
---|---|
bin | 11001001111100011… |
… | …11110110000010011 |
3 | 1021222111001221202211 |
4 | 30213301332300103 |
5 | 210223343043121 |
6 | 10120441052551 |
7 | 656560531435 |
oct | 144761766023 |
9 | 37874057684 |
10 | 13552315411 |
11 | 5824a24178 |
12 | 2762787157 |
13 | 137c94305b |
14 | 927c5c655 |
15 | 544ba0ce1 |
hex | 327c7ec13 |
13552315411 has 2 divisors, whose sum is σ = 13552315412. Its totient is φ = 13552315410.
The previous prime is 13552315397. The next prime is 13552315417. The reversal of 13552315411 is 11451325531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13552315411 - 25 = 13552315379 is a prime.
It is a super-3 number, since 3×135523154113 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13552315417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6776157705 + 6776157706.
It is an arithmetic number, because the mean of its divisors is an integer number (6776157706).
Almost surely, 213552315411 is an apocalyptic number.
13552315411 is a deficient number, since it is larger than the sum of its proper divisors (1).
13552315411 is an equidigital number, since it uses as much as digits as its factorization.
13552315411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9000, while the sum is 31.
The spelling of 13552315411 in words is "thirteen billion, five hundred fifty-two million, three hundred fifteen thousand, four hundred eleven".
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