Base | Representation |
---|---|
bin | 11001001111100011… |
… | …11110110000011001 |
3 | 1021222111001221210001 |
4 | 30213301332300121 |
5 | 210223343043132 |
6 | 10120441053001 |
7 | 656560531444 |
oct | 144761766031 |
9 | 37874057701 |
10 | 13552315417 |
11 | 5824a24183 |
12 | 2762787161 |
13 | 137c943064 |
14 | 927c5c65b |
15 | 544ba0ce7 |
hex | 327c7ec19 |
13552315417 has 2 divisors, whose sum is σ = 13552315418. Its totient is φ = 13552315416.
The previous prime is 13552315411. The next prime is 13552315453. The reversal of 13552315417 is 71451325531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10122573321 + 3429742096 = 100611^2 + 58564^2 .
It is an emirp because it is prime and its reverse (71451325531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13552315417 is a prime.
It is not a weakly prime, because it can be changed into another prime (13552315411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6776157708 + 6776157709.
It is an arithmetic number, because the mean of its divisors is an integer number (6776157709).
Almost surely, 213552315417 is an apocalyptic number.
It is an amenable number.
13552315417 is a deficient number, since it is larger than the sum of its proper divisors (1).
13552315417 is an equidigital number, since it uses as much as digits as its factorization.
13552315417 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 63000, while the sum is 37.
The spelling of 13552315417 in words is "thirteen billion, five hundred fifty-two million, three hundred fifteen thousand, four hundred seventeen".
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