1355323403453 has 2 divisors, whose sum is σ = 1355323403454. Its totient is φ = 1355323403452.

The previous prime is 1355323403351. The next prime is 1355323403519. The reversal of 1355323403453 is 3543043235531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1203755676964 + 151567726489 = 1097158^2 + 389317^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355323403453 - 2²⁰ = 1355322354877 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1355323403453.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1355313403453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677661701726 + 677661701727.

It is an arithmetic number, because the mean of its divisors is an integer number (677661701727).

Almost surely, 2^{1355323403453} is an apocalyptic number.

It is an amenable number.

1355323403453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355323403453 is an equidigital number, since it uses as much as digits as its factorization.

1355323403453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972000, while the sum is 41.

Adding to 1355323403453 its reverse (3543043235531), we get a palindrome (4898366638984).

The spelling of 1355323403453 in words is "one trillion, three hundred fifty-five billion, three hundred twenty-three million, four hundred three thousand, four hundred fifty-three".