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13553420183 is a prime number
BaseRepresentation
bin11001001111101100…
…01100011110010111
31021222120011002020022
430213312030132113
5210224133421213
610120520455355
7656603112362
oct144766143627
937876132208
1013553420183
115825609206
12276301a55b
13137cc3bb74
149280690d9
15544d1d308
hex327d8c797

13553420183 has 2 divisors, whose sum is σ = 13553420184. Its totient is φ = 13553420182.

The previous prime is 13553420173. The next prime is 13553420239. The reversal of 13553420183 is 38102435531.

It is a weak prime.

It is an emirp because it is prime and its reverse (38102435531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13553420183 - 232 = 9258452887 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13553420173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6776710091 + 6776710092.

It is an arithmetic number, because the mean of its divisors is an integer number (6776710092).

Almost surely, 213553420183 is an apocalyptic number.

13553420183 is a deficient number, since it is larger than the sum of its proper divisors (1).

13553420183 is an equidigital number, since it uses as much as digits as its factorization.

13553420183 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 13553420183 in words is "thirteen billion, five hundred fifty-three million, four hundred twenty thousand, one hundred eighty-three".