Base | Representation |
---|---|
bin | 111111000111011010… |
… | …0001110000111110001 |
3 | 110221212000111110001001 |
4 | 1332032310032013301 |
5 | 4210041222241202 |
6 | 142133301242001 |
7 | 12535544221663 |
oct | 1761664160761 |
9 | 427760443031 |
10 | 135540040177 |
11 | 52533901333 |
12 | 22328103301 |
13 | ca20897409 |
14 | 67bb186533 |
15 | 37d43e1d87 |
hex | 1f8ed0e1f1 |
135540040177 has 2 divisors, whose sum is σ = 135540040178. Its totient is φ = 135540040176.
The previous prime is 135540040147. The next prime is 135540040241. The reversal of 135540040177 is 771040045531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 78894136161 + 56645904016 = 280881^2 + 238004^2 .
It is a cyclic number.
It is not a de Polignac number, because 135540040177 - 211 = 135540038129 is a prime.
It is a super-2 number, since 2×1355400401772 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (135540040147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67770020088 + 67770020089.
It is an arithmetic number, because the mean of its divisors is an integer number (67770020089).
Almost surely, 2135540040177 is an apocalyptic number.
It is an amenable number.
135540040177 is a deficient number, since it is larger than the sum of its proper divisors (1).
135540040177 is an equidigital number, since it uses as much as digits as its factorization.
135540040177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58800, while the sum is 37.
The spelling of 135540040177 in words is "one hundred thirty-five billion, five hundred forty million, forty thousand, one hundred seventy-seven".
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