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135540040241 is a prime number
BaseRepresentation
bin111111000111011010…
…0001110001000110001
3110221212000111110010102
41332032310032020301
54210041222241431
6142133301242145
712535544222114
oct1761664161061
9427760443112
10135540040241
1152533901391
1222328103355
13ca20897458
1467bb18657b
1537d43e1dcb
hex1f8ed0e231

135540040241 has 2 divisors, whose sum is σ = 135540040242. Its totient is φ = 135540040240.

The previous prime is 135540040177. The next prime is 135540040261. The reversal of 135540040241 is 142040045531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134893863841 + 646176400 = 367279^2 + 25420^2 .

It is an emirp because it is prime and its reverse (142040045531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135540040241 - 26 = 135540040177 is a prime.

It is a super-2 number, since 2×1355400402412 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135540040261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67770020120 + 67770020121.

It is an arithmetic number, because the mean of its divisors is an integer number (67770020121).

Almost surely, 2135540040241 is an apocalyptic number.

It is an amenable number.

135540040241 is a deficient number, since it is larger than the sum of its proper divisors (1).

135540040241 is an equidigital number, since it uses as much as digits as its factorization.

135540040241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9600, while the sum is 29.

Adding to 135540040241 its reverse (142040045531), we get a palindrome (277580085772).

The spelling of 135540040241 in words is "one hundred thirty-five billion, five hundred forty million, forty thousand, two hundred forty-one".