1355411403132 has 24 divisors (see below), whose sum is σ = 3162709477200. Its totient is φ = 451791962496.

The previous prime is 1355411403119. The next prime is 1355411403161. The reversal of 1355411403132 is 2313041145531.

It is a junction number, because it is equal to n+sod(n) for n = 1355411403093 and 1355411403102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 996457 + ... + 1924512.

It is an arithmetic number, because the mean of its divisors is an integer number (131779561550).

Almost surely, 2^{1355411403132} is an apocalyptic number.

1355411403132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1355411403132 is an abundant number, since it is smaller than the sum of its proper divisors (1807298074068).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1355411403132 is a wasteful number, since it uses less digits than its factorization.

1355411403132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2959645 (or 2959643 counting only the distinct ones).

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 1355411403132 its reverse (2313041145531), we get a palindrome (3668452548663).

The spelling of 1355411403132 in words is "one trillion, three hundred fifty-five billion, four hundred eleven million, four hundred three thousand, one hundred thirty-two".