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135543324040303 is a prime number
BaseRepresentation
bin11110110100011010100011…
…101011100101110001101111
3122202220211000022011101222211
4132310122203223211301233
5120231220211423242203
61200135424330151251
740356452632463554
oct3664324353456157
9582824008141884
10135543324040303
113a2086678a4973
1213251254b82527
135a828b03c820a
1425684909aca2b
1510a0bd6135c6d
hex7b46a3ae5c6f

135543324040303 has 2 divisors, whose sum is σ = 135543324040304. Its totient is φ = 135543324040302.

The previous prime is 135543324040297. The next prime is 135543324040307. The reversal of 135543324040303 is 303040423345531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135543324040303 - 237 = 135405885086831 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135543324040307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67771662020151 + 67771662020152.

It is an arithmetic number, because the mean of its divisors is an integer number (67771662020152).

Almost surely, 2135543324040303 is an apocalyptic number.

135543324040303 is a deficient number, since it is larger than the sum of its proper divisors (1).

135543324040303 is an equidigital number, since it uses as much as digits as its factorization.

135543324040303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 777600, while the sum is 40.

Adding to 135543324040303 its reverse (303040423345531), we get a palindrome (438583747385834).

The spelling of 135543324040303 in words is "one hundred thirty-five trillion, five hundred forty-three billion, three hundred twenty-four million, forty thousand, three hundred three".