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1355442017 is a prime number
BaseRepresentation
bin101000011001010…
…0110011101100001
310111110111120220012
41100302212131201
510233443121032
6342255454305
745406031666
oct12062463541
93443446805
101355442017
11636125716
12319b27395
13187a7a3c7
14cc033a6d
157dee26b2
hex50ca6761

1355442017 has 2 divisors, whose sum is σ = 1355442018. Its totient is φ = 1355442016.

The previous prime is 1355441999. The next prime is 1355442037. The reversal of 1355442017 is 7102445531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1270138321 + 85303696 = 35639^2 + 9236^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355442017 - 212 = 1355437921 is a prime.

It is a super-2 number, since 2×13554420172 = 3674446122898056578, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1355442037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677721008 + 677721009.

It is an arithmetic number, because the mean of its divisors is an integer number (677721009).

Almost surely, 21355442017 is an apocalyptic number.

It is an amenable number.

1355442017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355442017 is an equidigital number, since it uses as much as digits as its factorization.

1355442017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 32.

The square root of 1355442017 is about 36816.3281303283. The cubic root of 1355442017 is about 1106.6925372071.

Adding to 1355442017 its reverse (7102445531), we get a palindrome (8457887548).

The spelling of 1355442017 in words is "one billion, three hundred fifty-five million, four hundred forty-two thousand, seventeen".