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135545002619837 is a prime number
BaseRepresentation
bin11110110100011100000111…
…101110110111001110111101
3122202220222100021201002020012
4132310130013232313032331
5120231232131132313322
61200140303052033005
740356542344252466
oct3664340756671675
9582828307632205
10135545002619837
113a209349367588
1213251643162765
135a82aba0b4945
1425685ad8b9d6d
1510a0c836a7ae2
hex7b4707bb73bd

135545002619837 has 2 divisors, whose sum is σ = 135545002619838. Its totient is φ = 135545002619836.

The previous prime is 135545002619821. The next prime is 135545002619933. The reversal of 135545002619837 is 738916200545531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132980427777796 + 2564574842041 = 11531714^2 + 1601429^2 .

It is an emirp because it is prime and its reverse (738916200545531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135545002619837 - 24 = 135545002619821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135545002669837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67772501309918 + 67772501309919.

It is an arithmetic number, because the mean of its divisors is an integer number (67772501309919).

It is a 1-persistent number, because it is pandigital, but 2⋅135545002619837 = 271090005239674 is not.

Almost surely, 2135545002619837 is an apocalyptic number.

It is an amenable number.

135545002619837 is a deficient number, since it is larger than the sum of its proper divisors (1).

135545002619837 is an equidigital number, since it uses as much as digits as its factorization.

135545002619837 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27216000, while the sum is 59.

The spelling of 135545002619837 in words is "one hundred thirty-five trillion, five hundred forty-five billion, two million, six hundred nineteen thousand, eight hundred thirty-seven".