Base | Representation |
---|---|
bin | 111111000111100100… |
… | …1000110000111001101 |
3 | 110221212101210110111212 |
4 | 1332033021012013031 |
5 | 4210044122344042 |
6 | 142134014424205 |
7 | 12535641562661 |
oct | 1761711060715 |
9 | 427771713455 |
10 | 135545512397 |
11 | 525369a9729 |
12 | 22329b02065 |
13 | ca21a62109 |
14 | 67bbbac8a1 |
15 | 37d4b23482 |
hex | 1f8f2461cd |
135545512397 has 2 divisors, whose sum is σ = 135545512398. Its totient is φ = 135545512396.
The previous prime is 135545512379. The next prime is 135545512409. The reversal of 135545512397 is 793215545531.
Together with previous prime (135545512379) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96280504681 + 39265007716 = 310291^2 + 198154^2 .
It is a cyclic number.
It is not a de Polignac number, because 135545512397 - 234 = 118365643213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135545512997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67772756198 + 67772756199.
It is an arithmetic number, because the mean of its divisors is an integer number (67772756199).
Almost surely, 2135545512397 is an apocalyptic number.
It is an amenable number.
135545512397 is a deficient number, since it is larger than the sum of its proper divisors (1).
135545512397 is an equidigital number, since it uses as much as digits as its factorization.
135545512397 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2835000, while the sum is 50.
The spelling of 135545512397 in words is "one hundred thirty-five billion, five hundred forty-five million, five hundred twelve thousand, three hundred ninety-seven".
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