Base | Representation |
---|---|
bin | 10011101110010111011… |
… | …110101111000110100001 |
3 | 11210120200001210222201020 |
4 | 103232113132233012201 |
5 | 134201433231140410 |
6 | 2514404332400053 |
7 | 166633315610301 |
oct | 23562736570641 |
9 | 4716601728636 |
10 | 1355456115105 |
11 | 482933705284 |
12 | 19a843616029 |
13 | 9aa85353c31 |
14 | 4986678b601 |
15 | 253d27bba70 |
hex | 13b977af1a1 |
1355456115105 has 32 divisors (see below), whose sum is σ = 2224462141440. Its totient is φ = 704412730560.
The previous prime is 1355456115103. The next prime is 1355456115113. The reversal of 1355456115105 is 5015116545531.
It is a happy number.
It is not a de Polignac number, because 1355456115105 - 21 = 1355456115103 is a prime.
It is a super-2 number, since 2×13554561151052 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1355456115103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2237481 + ... + 2777990.
It is an arithmetic number, because the mean of its divisors is an integer number (69514441920).
Almost surely, 21355456115105 is an apocalyptic number.
1355456115105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1355456115105 is a deficient number, since it is larger than the sum of its proper divisors (869006026335).
1355456115105 is a wasteful number, since it uses less digits than its factorization.
1355456115105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5015941.
The product of its (nonzero) digits is 225000, while the sum is 42.
The spelling of 1355456115105 in words is "one trillion, three hundred fifty-five billion, four hundred fifty-six million, one hundred fifteen thousand, one hundred five".
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