Search a number
-
+
135551051201 is a prime number
BaseRepresentation
bin111111000111101111…
…0001110010111000001
3110221212210012212022202
41332033132032113001
54210102032114301
6142134333242545
712536036632046
oct1761736162701
9427783185282
10135551051201
115253a042055
122232b933455
13ca22c51207
1467bc8111cd
1537d536966b
hex1f8f78e5c1

135551051201 has 2 divisors, whose sum is σ = 135551051202. Its totient is φ = 135551051200.

The previous prime is 135551051179. The next prime is 135551051203. The reversal of 135551051201 is 102150155531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122962435600 + 12588615601 = 350660^2 + 112199^2 .

It is a cyclic number.

It is not a de Polignac number, because 135551051201 - 218 = 135550789057 is a prime.

It is a super-2 number, since 2×1355510512012 (a number of 23 digits) contains 22 as substring.

Together with 135551051203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (135551051203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67775525600 + 67775525601.

It is an arithmetic number, because the mean of its divisors is an integer number (67775525601).

Almost surely, 2135551051201 is an apocalyptic number.

It is an amenable number.

135551051201 is a deficient number, since it is larger than the sum of its proper divisors (1).

135551051201 is an equidigital number, since it uses as much as digits as its factorization.

135551051201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3750, while the sum is 29.

The spelling of 135551051201 in words is "one hundred thirty-five billion, five hundred fifty-one million, fifty-one thousand, two hundred one".