Base | Representation |
---|---|
bin | 10011101110100010011… |
… | …110011110111100011001 |
3 | 11210121010220221201002001 |
4 | 103232202132132330121 |
5 | 134202322443121142 |
6 | 2514434522441001 |
7 | 166641015650206 |
oct | 23564236367431 |
9 | 4717126851061 |
10 | 1355640598297 |
11 | 482a1885a227 |
12 | 19a895363161 |
13 | 9aab463759b |
14 | 49883090cad |
15 | 253e3aad5b7 |
hex | 13ba279ef19 |
1355640598297 has 2 divisors, whose sum is σ = 1355640598298. Its totient is φ = 1355640598296.
The previous prime is 1355640598223. The next prime is 1355640598303. The reversal of 1355640598297 is 7928950465531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 790713986841 + 564926611456 = 889221^2 + 751616^2 .
It is a cyclic number.
It is not a de Polignac number, because 1355640598297 - 223 = 1355632209689 is a prime.
It is a super-2 number, since 2×13556405982972 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1355640598397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677820299148 + 677820299149.
It is an arithmetic number, because the mean of its divisors is an integer number (677820299149).
It is a 1-persistent number, because it is pandigital, but 2⋅1355640598297 = 2711281196594 is not.
Almost surely, 21355640598297 is an apocalyptic number.
It is an amenable number.
1355640598297 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355640598297 is an equidigital number, since it uses as much as digits as its factorization.
1355640598297 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648000, while the sum is 64.
The spelling of 1355640598297 in words is "one trillion, three hundred fifty-five billion, six hundred forty million, five hundred ninety-eight thousand, two hundred ninety-seven".
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