Base | Representation |
---|---|
bin | 10011101110100010100… |
… | …110001010100101001111 |
3 | 11210121011001202000102101 |
4 | 103232202212022211033 |
5 | 134202324002041142 |
6 | 2514435033535531 |
7 | 166641042035203 |
oct | 23564246124517 |
9 | 4717131660371 |
10 | 1355642612047 |
11 | 482a19a05189 |
12 | 19a895b745a7 |
13 | 9aab4b91059 |
14 | 49883456b03 |
15 | 253e3d5a0b7 |
hex | 13ba298a94f |
1355642612047 has 2 divisors, whose sum is σ = 1355642612048. Its totient is φ = 1355642612046.
The previous prime is 1355642612041. The next prime is 1355642612081. The reversal of 1355642612047 is 7402162465531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1355642612047 - 211 = 1355642609999 is a prime.
It is a super-2 number, since 2×13556426120472 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1355642611988 and 1355642612006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1355642612041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677821306023 + 677821306024.
It is an arithmetic number, because the mean of its divisors is an integer number (677821306024).
Almost surely, 21355642612047 is an apocalyptic number.
1355642612047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355642612047 is an equidigital number, since it uses as much as digits as its factorization.
1355642612047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1209600, while the sum is 46.
The spelling of 1355642612047 in words is "one trillion, three hundred fifty-five billion, six hundred forty-two million, six hundred twelve thousand, forty-seven".
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