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1355828101181 is a prime number
BaseRepresentation
bin10011101110101101101…
…001110000000000111101
311210121121222202211200022
4103232231221300000331
5134203213443214211
62514505301341525
7166645453464641
oct23565551600075
94717558684608
101355828101181
11483004686994
1219a9281078a5
139ab14437538
144989dd3cc21
1525405299bdb
hex13bada7003d

1355828101181 has 2 divisors, whose sum is σ = 1355828101182. Its totient is φ = 1355828101180.

The previous prime is 1355828101049. The next prime is 1355828101241. The reversal of 1355828101181 is 1811018285531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1328565137956 + 27262963225 = 1152634^2 + 165115^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355828101181 - 226 = 1355760992317 is a prime.

It is a super-2 number, since 2×13558281011812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1355828101781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677914050590 + 677914050591.

It is an arithmetic number, because the mean of its divisors is an integer number (677914050591).

Almost surely, 21355828101181 is an apocalyptic number.

It is an amenable number.

1355828101181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355828101181 is an equidigital number, since it uses as much as digits as its factorization.

1355828101181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 76800, while the sum is 44.

The spelling of 1355828101181 in words is "one trillion, three hundred fifty-five billion, eight hundred twenty-eight million, one hundred one thousand, one hundred eighty-one".