Base | Representation |
---|---|
bin | 10011101110111000110… |
… | …001001111000001000111 |
3 | 11210122002222201121011211 |
4 | 103232320301033001013 |
5 | 134204104220100201 |
6 | 2514540003112251 |
7 | 166653210012604 |
oct | 23567061170107 |
9 | 4718088647154 |
10 | 1356014612551 |
11 | 48309a996715 |
12 | 19a97a672687 |
13 | 9ab43c7b0b1 |
14 | 498baa0d6ab |
15 | 2541683c651 |
hex | 13bb8c4f047 |
1356014612551 has 2 divisors, whose sum is σ = 1356014612552. Its totient is φ = 1356014612550.
The previous prime is 1356014612543. The next prime is 1356014612573. The reversal of 1356014612551 is 1552164106531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1356014612551 - 23 = 1356014612543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1356014612581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 678007306275 + 678007306276.
It is an arithmetic number, because the mean of its divisors is an integer number (678007306276).
Almost surely, 21356014612551 is an apocalyptic number.
1356014612551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1356014612551 is an equidigital number, since it uses as much as digits as its factorization.
1356014612551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108000, while the sum is 40.
The spelling of 1356014612551 in words is "one trillion, three hundred fifty-six billion, fourteen million, six hundred twelve thousand, five hundred fifty-one".
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