Base | Representation |
---|---|
bin | 11001010000100000… |
… | …01001101001010101 |
3 | 1022000000221202210011 |
4 | 30220100021221111 |
5 | 210232404134331 |
6 | 10121322400221 |
7 | 660015001516 |
oct | 145020115125 |
9 | 38000852704 |
10 | 13560224341 |
11 | 5829436284 |
12 | 2765360071 |
13 | 1381481bb1 |
14 | 928d1aa0d |
15 | 5457143b1 |
hex | 328409a55 |
13560224341 has 2 divisors, whose sum is σ = 13560224342. Its totient is φ = 13560224340.
The previous prime is 13560224329. The next prime is 13560224357. The reversal of 13560224341 is 14342206531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9906021841 + 3654202500 = 99529^2 + 60450^2 .
It is a cyclic number.
It is not a de Polignac number, because 13560224341 - 25 = 13560224309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13560224371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6780112170 + 6780112171.
It is an arithmetic number, because the mean of its divisors is an integer number (6780112171).
Almost surely, 213560224341 is an apocalyptic number.
It is an amenable number.
13560224341 is a deficient number, since it is larger than the sum of its proper divisors (1).
13560224341 is an equidigital number, since it uses as much as digits as its factorization.
13560224341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
The spelling of 13560224341 in words is "thirteen billion, five hundred sixty million, two hundred twenty-four thousand, three hundred forty-one".
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