Base | Representation |
---|---|
bin | 111111001001010001… |
… | …0000010000010000101 |
3 | 110222000100210200110221 |
4 | 1332102202002002011 |
5 | 4210203202142213 |
6 | 142143405344341 |
7 | 12540232135315 |
oct | 1762242020205 |
9 | 428010720427 |
10 | 135602380933 |
11 | 52566010918 |
12 | 22344b680b1 |
13 | ca30783936 |
14 | 67c5573445 |
15 | 37d9b0838d |
hex | 1f92882085 |
135602380933 has 2 divisors, whose sum is σ = 135602380934. Its totient is φ = 135602380932.
The previous prime is 135602380763. The next prime is 135602380987. The reversal of 135602380933 is 339083206531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75313471489 + 60288909444 = 274433^2 + 245538^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135602380933 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 135602380933.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135602380993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67801190466 + 67801190467.
It is an arithmetic number, because the mean of its divisors is an integer number (67801190467).
Almost surely, 2135602380933 is an apocalyptic number.
It is an amenable number.
135602380933 is a deficient number, since it is larger than the sum of its proper divisors (1).
135602380933 is an equidigital number, since it uses as much as digits as its factorization.
135602380933 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 349920, while the sum is 43.
The spelling of 135602380933 in words is "one hundred thirty-five billion, six hundred two million, three hundred eighty thousand, nine hundred thirty-three".
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