Base | Representation |
---|---|
bin | 11110110101010010110000… |
… | …001100001011010011010111 |
3 | 122210010120202110102002011121 |
4 | 132311102300030023103113 |
5 | 120233212300320420401 |
6 | 1200223244001144411 |
7 | 40364020123144054 |
oct | 3665226014132327 |
9 | 583116673362147 |
10 | 135603663451351 |
11 | 3a231210924527 |
12 | 13260a9462b107 |
13 | 5a884a8271934 |
14 | 256b37657402b |
15 | 10a256857eca1 |
hex | 7b54b030b4d7 |
135603663451351 has 2 divisors, whose sum is σ = 135603663451352. Its totient is φ = 135603663451350.
The previous prime is 135603663451301. The next prime is 135603663451387. The reversal of 135603663451351 is 153154366306531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135603663451351 - 215 = 135603663418583 is a prime.
It is a super-2 number, since 2×1356036634513512 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135603663451301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67801831725675 + 67801831725676.
It is an arithmetic number, because the mean of its divisors is an integer number (67801831725676).
Almost surely, 2135603663451351 is an apocalyptic number.
135603663451351 is a deficient number, since it is larger than the sum of its proper divisors (1).
135603663451351 is an equidigital number, since it uses as much as digits as its factorization.
135603663451351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748000, while the sum is 52.
The spelling of 135603663451351 in words is "one hundred thirty-five trillion, six hundred three billion, six hundred sixty-three million, four hundred fifty-one thousand, three hundred fifty-one".
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