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135623234240537 is a prime number
BaseRepresentation
bin11110110101100100111110…
…101100110100000000011001
3122210012110021101022011212112
4132311210332230310000121
5120234022340431144122
61200240241555122105
740365312114125351
oct3665447654640031
9583173241264775
10135623234240537
113a23954404706a
12132648368a3335
135a8a2a6a4b274
14256c2b184db61
1510a2d117b72e2
hex7b593eb34019

135623234240537 has 2 divisors, whose sum is σ = 135623234240538. Its totient is φ = 135623234240536.

The previous prime is 135623234240503. The next prime is 135623234240657. The reversal of 135623234240537 is 735042432326531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87374428910041 + 48248805330496 = 9347429^2 + 6946136^2 .

It is a cyclic number.

It is not a de Polignac number, because 135623234240537 - 28 = 135623234240281 is a prime.

It is not a weakly prime, because it can be changed into another prime (135623234242537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67811617120268 + 67811617120269.

It is an arithmetic number, because the mean of its divisors is an integer number (67811617120269).

Almost surely, 2135623234240537 is an apocalyptic number.

It is an amenable number.

135623234240537 is a deficient number, since it is larger than the sum of its proper divisors (1).

135623234240537 is an equidigital number, since it uses as much as digits as its factorization.

135623234240537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10886400, while the sum is 50.

The spelling of 135623234240537 in words is "one hundred thirty-five trillion, six hundred twenty-three billion, two hundred thirty-four million, two hundred forty thousand, five hundred thirty-seven".