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135623234240503 is a prime number
BaseRepresentation
bin11110110101100100111110…
…101100110011111111110111
3122210012110021101022011211021
4132311210332230303333313
5120234022340431144003
61200240241555122011
740365312114125302
oct3665447654637767
9583173241264737
10135623234240503
113a239544047039
12132648368a3307
135a8a2a6a4b249
14256c2b184db39
1510a2d117b72bd
hex7b593eb33ff7

135623234240503 has 2 divisors, whose sum is σ = 135623234240504. Its totient is φ = 135623234240502.

The previous prime is 135623234240497. The next prime is 135623234240537. The reversal of 135623234240503 is 305042432326531.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (305042432326531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135623234240503 is a prime.

It is a super-3 number, since 3×1356232342405033 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 135623234240503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135623234240203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67811617120251 + 67811617120252.

It is an arithmetic number, because the mean of its divisors is an integer number (67811617120252).

Almost surely, 2135623234240503 is an apocalyptic number.

135623234240503 is a deficient number, since it is larger than the sum of its proper divisors (1).

135623234240503 is an equidigital number, since it uses as much as digits as its factorization.

135623234240503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1555200, while the sum is 43.

The spelling of 135623234240503 in words is "one hundred thirty-five trillion, six hundred twenty-three billion, two hundred thirty-four million, two hundred forty thousand, five hundred three".