Base | Representation |
---|---|
bin | 111111001010010101… |
… | …1100100001110000101 |
3 | 110222002212122101221101 |
4 | 1332110223210032011 |
5 | 4210241414402233 |
6 | 142151134220101 |
7 | 12541150446316 |
oct | 1762453441605 |
9 | 428085571841 |
10 | 135638434693 |
11 | 525843a6613 |
12 | 22355054631 |
13 | ca38098218 |
14 | 67ca27a60d |
15 | 37dcd7ac7d |
hex | 1f94ae4385 |
135638434693 has 2 divisors, whose sum is σ = 135638434694. Its totient is φ = 135638434692.
The previous prime is 135638434663. The next prime is 135638434759. The reversal of 135638434693 is 396434836531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 95791488004 + 39846946689 = 309502^2 + 199617^2 .
It is a cyclic number.
It is not a de Polignac number, because 135638434693 - 233 = 127048500101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135638434663) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67819217346 + 67819217347.
It is an arithmetic number, because the mean of its divisors is an integer number (67819217347).
Almost surely, 2135638434693 is an apocalyptic number.
It is an amenable number.
135638434693 is a deficient number, since it is larger than the sum of its proper divisors (1).
135638434693 is an equidigital number, since it uses as much as digits as its factorization.
135638434693 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16796160, while the sum is 55.
The spelling of 135638434693 in words is "one hundred thirty-five billion, six hundred thirty-eight million, four hundred thirty-four thousand, six hundred ninety-three".
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