Base | Representation |
---|---|
bin | 11110110110000010000111… |
… | …010010100010010110100011 |
3 | 122210022110000112001220211011 |
4 | 132312002013102202112203 |
5 | 120240030422304012243 |
6 | 1200302454050201351 |
7 | 40400500250036446 |
oct | 3666020722422643 |
9 | 583273015056734 |
10 | 135654516860323 |
11 | 3a25083729734a |
12 | 1326a907283257 |
13 | 5a90220a74486 |
14 | 256d9dc37365d |
15 | 10a3a42ceb89d |
hex | 7b60874a25a3 |
135654516860323 has 2 divisors, whose sum is σ = 135654516860324. Its totient is φ = 135654516860322.
The previous prime is 135654516860321. The next prime is 135654516860377. The reversal of 135654516860323 is 323068615456531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135654516860323 - 21 = 135654516860321 is a prime.
Together with 135654516860321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (135654516860321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67827258430161 + 67827258430162.
It is an arithmetic number, because the mean of its divisors is an integer number (67827258430162).
Almost surely, 2135654516860323 is an apocalyptic number.
135654516860323 is a deficient number, since it is larger than the sum of its proper divisors (1).
135654516860323 is an equidigital number, since it uses as much as digits as its factorization.
135654516860323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656000, while the sum is 58.
The spelling of 135654516860323 in words is "one hundred thirty-five trillion, six hundred fifty-four billion, five hundred sixteen million, eight hundred sixty thousand, three hundred twenty-three".
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