Base | Representation |
---|---|
bin | 11110110110000100111100… |
… | …010100111111110010000011 |
3 | 122210022201212012022210211212 |
4 | 132312010330110333302003 |
5 | 120240103132332300001 |
6 | 1200304115310400335 |
7 | 40400635440611504 |
oct | 3666047424776203 |
9 | 583281765283755 |
10 | 135657554181251 |
11 | 3a252055828533 |
12 | 1326b4145000ab |
13 | 5a905b60c4cab |
14 | 256dc098d2bab |
15 | 10a3b6e7b37bb |
hex | 7b613c53fc83 |
135657554181251 has 2 divisors, whose sum is σ = 135657554181252. Its totient is φ = 135657554181250.
The previous prime is 135657554181239. The next prime is 135657554181263. The reversal of 135657554181251 is 152181455756531.
It is a balanced prime because it is at equal distance from previous prime (135657554181239) and next prime (135657554181263).
It is a cyclic number.
It is not a de Polignac number, because 135657554181251 - 222 = 135657549986947 is a prime.
It is not a weakly prime, because it can be changed into another prime (135657154181251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67828777090625 + 67828777090626.
It is an arithmetic number, because the mean of its divisors is an integer number (67828777090626).
Almost surely, 2135657554181251 is an apocalyptic number.
135657554181251 is a deficient number, since it is larger than the sum of its proper divisors (1).
135657554181251 is an equidigital number, since it uses as much as digits as its factorization.
135657554181251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25200000, while the sum is 59.
The spelling of 135657554181251 in words is "one hundred thirty-five trillion, six hundred fifty-seven billion, five hundred fifty-four million, one hundred eighty-one thousand, two hundred fifty-one".
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