Base | Representation |
---|---|
bin | 10011101111110001000… |
… | …111011001111001110001 |
3 | 11210201112212112122011201 |
4 | 103233301013121321301 |
5 | 134213023221322101 |
6 | 2515213453011201 |
7 | 200015506152031 |
oct | 23576107317161 |
9 | 4721485478151 |
10 | 1356959948401 |
11 | 483535573512 |
12 | 19aba3183b01 |
13 | 9ac64a88c15 |
14 | 4996a3ab8c1 |
15 | 2546e821e01 |
hex | 13bf11d9e71 |
1356959948401 has 2 divisors, whose sum is σ = 1356959948402. Its totient is φ = 1356959948400.
The previous prime is 1356959948207. The next prime is 1356959948419. The reversal of 1356959948401 is 1048499596531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1100822738401 + 256137210000 = 1049201^2 + 506100^2 .
It is a cyclic number.
It is not a de Polignac number, because 1356959948401 - 217 = 1356959817329 is a prime.
It is not a weakly prime, because it can be changed into another prime (1356959948501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 678479974200 + 678479974201.
It is an arithmetic number, because the mean of its divisors is an integer number (678479974201).
Almost surely, 21356959948401 is an apocalyptic number.
It is an amenable number.
1356959948401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1356959948401 is an equidigital number, since it uses as much as digits as its factorization.
1356959948401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41990400, while the sum is 64.
The spelling of 1356959948401 in words is "one trillion, three hundred fifty-six billion, nine hundred fifty-nine million, nine hundred forty-eight thousand, four hundred one".
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