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135767954423807 is a prime number
BaseRepresentation
bin11110110111101011110000…
…101100011111111111111111
3122210201021211011212012210022
4132313223300230133333333
5120243410232313030212
61200430534235002355
740411624322314046
oct3667536054377777
9583637734765708
10135767954423807
113a294958899812
12132888a52993bb
135a9ab2b4b99c4
1425752bdd0155d
1510a6981abb772
hex7b7af0b1ffff

135767954423807 has 2 divisors, whose sum is σ = 135767954423808. Its totient is φ = 135767954423806.

The previous prime is 135767954423767. The next prime is 135767954423819. The reversal of 135767954423807 is 708324459767531.

It is a strong prime.

It is an emirp because it is prime and its reverse (708324459767531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135767954423807 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135760954423807) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67883977211903 + 67883977211904.

It is an arithmetic number, because the mean of its divisors is an integer number (67883977211904).

It is a 2-persistent number, because it is pandigital, and so is 2⋅135767954423807 = 271535908847614, but 3⋅135767954423807 = 407303863271421 is not.

Almost surely, 2135767954423807 is an apocalyptic number.

135767954423807 is a deficient number, since it is larger than the sum of its proper divisors (1).

135767954423807 is an equidigital number, since it uses as much as digits as its factorization.

135767954423807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1066867200, while the sum is 71.

The spelling of 135767954423807 in words is "one hundred thirty-five trillion, seven hundred sixty-seven billion, nine hundred fifty-four million, four hundred twenty-three thousand, eight hundred seven".