Base | Representation |
---|---|
bin | 10000001100111… |
… | …01001010100011 |
3 | 100110201221112121 |
4 | 20012131022203 |
5 | 234243110201 |
6 | 21253005111 |
7 | 3240134134 |
oct | 1006351243 |
9 | 313657477 |
10 | 135910051 |
11 | 6a799262 |
12 | 39623797 |
13 | 22207864 |
14 | 1409bc8b |
15 | bde99a1 |
hex | 819d2a3 |
135910051 has 2 divisors, whose sum is σ = 135910052. Its totient is φ = 135910050.
The previous prime is 135910003. The next prime is 135910063. The reversal of 135910051 is 150019531.
It is a strong prime.
It is an emirp because it is prime and its reverse (150019531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135910051 - 27 = 135909923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135909998 and 135910025.
It is not a weakly prime, because it can be changed into another prime (135910001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67955025 + 67955026.
It is an arithmetic number, because the mean of its divisors is an integer number (67955026).
Almost surely, 2135910051 is an apocalyptic number.
135910051 is a deficient number, since it is larger than the sum of its proper divisors (1).
135910051 is an equidigital number, since it uses as much as digits as its factorization.
135910051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 675, while the sum is 25.
The square root of 135910051 is about 11658.0466202533. The cubic root of 135910051 is about 514.1429185159.
Adding to 135910051 its reverse (150019531), we get a palindrome (285929582).
The spelling of 135910051 in words is "one hundred thirty-five million, nine hundred ten thousand, fifty-one".
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