Base | Representation |
---|---|
bin | 111111010010101011… |
… | …1100011100100000101 |
3 | 110222211101110012121101 |
4 | 1332211113203210011 |
5 | 4211330102324142 |
6 | 142235015020101 |
7 | 12551120232043 |
oct | 1764527434405 |
9 | 428741405541 |
10 | 135918401797 |
11 | 52708437a92 |
12 | 2241296a631 |
13 | ca810a0929 |
14 | 6815517393 |
15 | 380772e0b7 |
hex | 1fa55e3905 |
135918401797 has 2 divisors, whose sum is σ = 135918401798. Its totient is φ = 135918401796.
The previous prime is 135918401747. The next prime is 135918401807. The reversal of 135918401797 is 797104819531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 121721440996 + 14196960801 = 348886^2 + 119151^2 .
It is an emirp because it is prime and its reverse (797104819531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135918401797 - 27 = 135918401669 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135918401747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67959200898 + 67959200899.
It is an arithmetic number, because the mean of its divisors is an integer number (67959200899).
Almost surely, 2135918401797 is an apocalyptic number.
It is an amenable number.
135918401797 is a deficient number, since it is larger than the sum of its proper divisors (1).
135918401797 is an equidigital number, since it uses as much as digits as its factorization.
135918401797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1905120, while the sum is 55.
The spelling of 135918401797 in words is "one hundred thirty-five billion, nine hundred eighteen million, four hundred one thousand, seven hundred ninety-seven".
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