Base | Representation |
---|---|
bin | 111111010010110010… |
… | …1010000010100111011 |
3 | 110222211122012122211121 |
4 | 1332211211100110323 |
5 | 4211332012234034 |
6 | 142235224010111 |
7 | 12551162610061 |
oct | 1764545202473 |
9 | 428748178747 |
10 | 135921993019 |
11 | 5270a47013a |
12 | 22414000937 |
13 | ca81a5a407 |
14 | 6815bb0031 |
15 | 3807bdd1b4 |
hex | 1fa595053b |
135921993019 has 2 divisors, whose sum is σ = 135921993020. Its totient is φ = 135921993018.
The previous prime is 135921993017. The next prime is 135921993041. The reversal of 135921993019 is 910399129531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135921993019 - 21 = 135921993017 is a prime.
It is a super-3 number, since 3×1359219930193 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 135921993017, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (135921993017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67960996509 + 67960996510.
It is an arithmetic number, because the mean of its divisors is an integer number (67960996510).
Almost surely, 2135921993019 is an apocalyptic number.
135921993019 is a deficient number, since it is larger than the sum of its proper divisors (1).
135921993019 is an equidigital number, since it uses as much as digits as its factorization.
135921993019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 590490, while the sum is 52.
The spelling of 135921993019 in words is "one hundred thirty-five billion, nine hundred twenty-one million, nine hundred ninety-three thousand, nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.250 sec. • engine limits •