Base | Representation |
---|---|
bin | 111111010011010111… |
… | …1000000010111100011 |
3 | 110222212222120220010022 |
4 | 1332212233000113203 |
5 | 4211401434420212 |
6 | 142241154224055 |
7 | 12551516131253 |
oct | 1764657002743 |
9 | 428788526108 |
10 | 135941326307 |
11 | 5271a375566 |
12 | 2241a58502b |
13 | ca85a69227 |
14 | 68185a3963 |
15 | 380975b772 |
hex | 1fa6bc05e3 |
135941326307 has 2 divisors, whose sum is σ = 135941326308. Its totient is φ = 135941326306.
The previous prime is 135941326291. The next prime is 135941326351. The reversal of 135941326307 is 703623149531.
It is an a-pointer prime, because the next prime (135941326351) can be obtained adding 135941326307 to its sum of digits (44).
It is a weak prime.
It is an emirp because it is prime and its reverse (703623149531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135941326307 - 24 = 135941326291 is a prime.
It is not a weakly prime, because it can be changed into another prime (135941326207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67970663153 + 67970663154.
It is an arithmetic number, because the mean of its divisors is an integer number (67970663154).
Almost surely, 2135941326307 is an apocalyptic number.
135941326307 is a deficient number, since it is larger than the sum of its proper divisors (1).
135941326307 is an equidigital number, since it uses as much as digits as its factorization.
135941326307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 408240, while the sum is 44.
The spelling of 135941326307 in words is "one hundred thirty-five billion, nine hundred forty-one million, three hundred twenty-six thousand, three hundred seven".
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