Base | Representation |
---|---|
bin | 10011110010001000010… |
… | …010101100110110100001 |
3 | 11210222002122002002020201 |
4 | 103302020102230312201 |
5 | 134233222021103332 |
6 | 2520313255105201 |
7 | 200135404423252 |
oct | 23621022546641 |
9 | 4728078062221 |
10 | 1359496269217 |
11 | 484617224919 |
12 | 19b590672201 |
13 | 9b27a394378 |
14 | 49b2b194b29 |
15 | 2556c3245e7 |
hex | 13c884acda1 |
1359496269217 has 2 divisors, whose sum is σ = 1359496269218. Its totient is φ = 1359496269216.
The previous prime is 1359496269203. The next prime is 1359496269247. The reversal of 1359496269217 is 7129626949531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1336465475136 + 23030794081 = 1156056^2 + 151759^2 .
It is an emirp because it is prime and its reverse (7129626949531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1359496269217 is a prime.
It is not a weakly prime, because it can be changed into another prime (1359496269247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 679748134608 + 679748134609.
It is an arithmetic number, because the mean of its divisors is an integer number (679748134609).
Almost surely, 21359496269217 is an apocalyptic number.
It is an amenable number.
1359496269217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1359496269217 is an equidigital number, since it uses as much as digits as its factorization.
1359496269217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 44089920, while the sum is 64.
The spelling of 1359496269217 in words is "one trillion, three hundred fifty-nine billion, four hundred ninety-six million, two hundred sixty-nine thousand, two hundred seventeen".
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