Base | Representation |
---|---|
bin | 11110111011000100010111… |
… | …101001110001100011110110 |
3 | 122211112112011012121101211121 |
4 | 132323010113221301203312 |
5 | 120311213044240122320 |
6 | 1201125441150454154 |
7 | 40434500033255521 |
oct | 3673042751614366 |
9 | 584475135541747 |
10 | 136000536254710 |
11 | 3a37455a209796 |
12 | 1330599450435a |
13 | 5ab6a45a51c5a |
14 | 258266529dbb8 |
15 | 10aca4565b8aa |
hex | 7bb117a718f6 |
136000536254710 has 16 divisors (see below), whose sum is σ = 244801938102336. Its totient is φ = 54399998314368.
The previous prime is 136000536254657. The next prime is 136000536254711. The reversal of 136000536254710 is 17452635000631.
It is a super-3 number, since 3×1360005362547103 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136000536254711) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24368862 + ... + 29425201.
It is an arithmetic number, because the mean of its divisors is an integer number (15300121131396).
Almost surely, 2136000536254710 is an apocalyptic number.
136000536254710 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
136000536254710 is a deficient number, since it is larger than the sum of its proper divisors (108801401847626).
136000536254710 is a wasteful number, since it uses less digits than its factorization.
136000536254710 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54046887.
The product of its (nonzero) digits is 453600, while the sum is 43.
The spelling of 136000536254710 in words is "one hundred thirty-six trillion, five hundred thirty-six million, two hundred fifty-four thousand, seven hundred ten".
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