Base | Representation |
---|---|
bin | 11110111011010001010001… |
… | …110000110010111110100101 |
3 | 122211120211221010022021021212 |
4 | 132323101101300302332211 |
5 | 120311424440343412231 |
6 | 1201140052334521205 |
7 | 40435500346640555 |
oct | 3673212160627645 |
9 | 584524833267255 |
10 | 136014396075941 |
11 | 3a37a4217735a9 |
12 | 13308602066205 |
13 | 5ab81442c02c6 |
14 | 25831bbcc7165 |
15 | 10ad0a730042b |
hex | 7bb451c32fa5 |
136014396075941 has 2 divisors, whose sum is σ = 136014396075942. Its totient is φ = 136014396075940.
The previous prime is 136014396075923. The next prime is 136014396075979. The reversal of 136014396075941 is 149570693410631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130278711160900 + 5735684915041 = 11413970^2 + 2394929^2 .
It is an emirp because it is prime and its reverse (149570693410631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136014396075941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136014396005941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68007198037970 + 68007198037971.
It is an arithmetic number, because the mean of its divisors is an integer number (68007198037971).
Almost surely, 2136014396075941 is an apocalyptic number.
It is an amenable number.
136014396075941 is a deficient number, since it is larger than the sum of its proper divisors (1).
136014396075941 is an equidigital number, since it uses as much as digits as its factorization.
136014396075941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14696640, while the sum is 59.
The spelling of 136014396075941 in words is "one hundred thirty-six trillion, fourteen billion, three hundred ninety-six million, seventy-five thousand, nine hundred forty-one".
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